Which statement about the evaporation temperature of R-134a at 0 psig is correct?

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Multiple Choice

Which statement about the evaporation temperature of R-134a at 0 psig is correct?

Explanation:
The evaporation temperature at a given pressure is the saturation temperature of the refrigerant at that pressure. At 0 psig, the pressure is essentially atmospheric (about 14.7 psia). For R-134a, the saturation temperature at that pressure is roughly -26°C, which converts to about -14.8°F—rounded to -15°F. So the evaporation temperature at 0 psig is about -15°F. The other numbers don’t match the known saturation point at atmospheric pressure.

The evaporation temperature at a given pressure is the saturation temperature of the refrigerant at that pressure. At 0 psig, the pressure is essentially atmospheric (about 14.7 psia). For R-134a, the saturation temperature at that pressure is roughly -26°C, which converts to about -14.8°F—rounded to -15°F. So the evaporation temperature at 0 psig is about -15°F. The other numbers don’t match the known saturation point at atmospheric pressure.

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